Searched refs:rootelement (Results 1 – 1 of 1) sorted by relevance
35 rootelement = None # root element of the XML tree variable164 global rootelement213 if rootelement is None:214 rootelement = lxml.etree.Element('refentrycontainer')221 refentry = lxml.etree.SubElement(rootelement, 'refentry')824 s = lxml.etree.tostring(rootelement, pretty_print=True, encoding='unicode')