Searched refs:div1_vals (Results 1 – 1 of 1) sorted by relevance
2628 int div1_vals[] = {7, 5, 3, 2}; in icl_mg_pll_find_divisors() local2635 for (i = 0; i < ARRAY_SIZE(div1_vals); i++) { in icl_mg_pll_find_divisors()2636 int div1 = div1_vals[i]; in icl_mg_pll_find_divisors()
